damn, no really ? how did you work that out ? thanks !
Here is a link to the amps vs output percent on page 5 : http://www.cree.com/products/pdf/XLampXM-L.pdf
At .7 amps the XM-l T6 is 100% which is 280 lumens min.
At 1.25 amps the XM-L T6 is about 162% which is about 450 lumens!
Of course, general rules in a flashlight with a reflector you would lose 30% so your OTF lumens in a FL would be around 315 lumens
cool tool...Register here and you will get detailed data about Cree LEDs:
http://pct.cree.com/
As a general rule of thumb, emitter efficiency drops as input current rises, so, these numbers will probably be a bit optimistic. I'd guess that you'd get around 440 emitter lumens at 1.25A, but, that also depends on the characteristics of the emitter itself. I know, nitpicking. I just thought that someone reading this might think that an XM-L making 280 lumens at 0.7A will make 1120 lumens at 2.8A when, in reality, it will make more like 900 lumens at 2.8A.
As a general rule of thumb, emitter efficiency drops as input current rises, so, these numbers will probably be a bit optimistic. I'd guess that you'd get around 440 emitter lumens at 1.25A, but, that also depends on the characteristics of the emitter itself. I know, nitpicking. I just thought that someone reading this might think that an XM-L making 280 lumens at 0.7A will make 1120 lumens at 2.8A when, in reality, it will make more like 900 lumens at 2.8A.
I'd guess that you'd get around 440 emitter lumens at 1.25A
Don't guess, use the Cree product characterization tool linked above...