My PD 32 draws about 1 amp at max brightness.
I checked the Amp draw of my Maelstrom last night, as I had never actually checked it. With a fully charged, older TrustFire 2500mAh cell, the light drew about 1.3A on turbo.
At about the same time as I was checking this, the thought occurred to me that these lights utilize a buck circuit, as I believe the PD32 does also. This means that once the circuit voltage reaches the Vf of the LED plus the driver overhead, the light is no longer in regulation, and the current draw from the cell begins to drop anyway.
My main point was that the voltage at which a protected cell's PCB triggers, is not the same as what the cell's OC voltage will read after the circuit has tripped. Depending on the type of cell, it's age and general condition, the OC voltage of a cell may be anywhere from close to the same as the protection circuit's trip point, at very low current levels, to as much as 0.5 Volt, or more higher, when the circuit trips at higher current levels. To add to this, the actual electronics of the light's driver can come into play, as well.
My best guess is that since the PD32 "looses levels" as the battery becomes depleted, a feature that the Maelstrom does not have, this allows the cell to be discharged farther, due to the decreased current demand at lower output levels. This, as I mentioned earlier, is a good reason not to rely on the protection circuit, as a cell can apparently be discharged to a much lower level, in the PD32. And again, I'm not saying you can't do that, but cells will last a lot longer if deep discharging is avoided.
Dave