Far from being expert, i wonder if this can be a quick and dirty way to evaluate (used) 18650 batteries:
1. Connect a small LED voltometer in parallel on ONE cell, check the number (V1).
2. Give to the cell a certain (charging) voltage (let us say 500mA momentarily, with a small typical USB wall charger), check the number again (V2).
3. V_difference = V2 - V1.
The greater the V_difference, the worst the battery is.
Is this approach right or wrong?
I hope this is not stupid enough, but the notion under is that "the worst the battery, the greater the impedance", but i i am not sure for that! :duh2:
1. Connect a small LED voltometer in parallel on ONE cell, check the number (V1).
2. Give to the cell a certain (charging) voltage (let us say 500mA momentarily, with a small typical USB wall charger), check the number again (V2).
3. V_difference = V2 - V1.
The greater the V_difference, the worst the battery is.
Is this approach right or wrong?
I hope this is not stupid enough, but the notion under is that "the worst the battery, the greater the impedance", but i i am not sure for that! :duh2: