9.6v in a maglite, longest runtime, what cells?

[waddup]

i have a mag64, 2 x D maglite (host) 8xAA cells in series =9.6v 1164 bulb.

estimated runtime = 25 minutes.(@1500 lumens)

im just wondering if i can maybe get a 6 x D mag or 4 or 3 and use litium cells and still arrive at 9.6v but have longer runtimes?

will lithiums behave ok used in such an application?

any thoughts?

 

[waddup]

if i put 6 x D cells @ 12,000 mah hours each thats

1.2v x 6 = 7.2v.

so the bulb would be 25% dimmer = 1000 lumens,

but run for much longer.


am i close?

 

[mdocod]

if i put 6 x D cells @ 12,000 mah hours each thats

1.2v x 6 = 7.2v.

so the bulb would be 25% dimmer = 1000 lumens,

but run for much longer.


am i close?

well.. first off, the WA1164 at 9.6V is ~1350 bulb lumen... 1500 lumens may happen fresh off the charger for a short while...

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Oh, FYI, taking 25% off of 1500 is 1125

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For the sake of argument, lets call it 1500 lumen on 8 NIMH cells.

Drop to 6 cells and here's the formula:

[(7.2V/9.6V)^3]x1500L=632L

Less than half the output... would be a total waste of electrical power in a flashlight, just use an ROP bulb instead in a 6D.


or you can just look here:
http://i61.photobucket.com/albums/h75/pike444/bulbs/1164.jpg
(from luxluthors destructive incan tests.)

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back to the original question: 3x32900 size LiFePO4 cells from batteryspace would fit in a 5D mag, requiring a 30mm dummy cell, and would roughly double your runtime... Might flash the bulb fresh from the charger....

other than that, there isn't any way to divide 3.7 into 9.6 and get a whole number, so you can't use LiCo or LiPo cells with an 1164, which really kills all energy dense solutions.

Your best bet is to go to a different bulb if you want a li-ion setup.

You could make a 3D Mag85 with D size Li-Ion cells, well over an hour runtime with similar output.

You could go simple, and just build a 6D ROP.