AvroArrow
Enlightened
Just a question for those more knowledgeable than myself regarding batteries. How do alkaline batteries behave when used in series? Basically what I want to know is will they be able to drive a boosted tri-lux setup, and if so, for how long?
Here's my proposed build setup:
Mag 3D
modamag PTS2-D
3x TX1K Lux3 stars
Fatman set for 700ma drive current
3x D cell alkalines or
4x C cell alkalines + PVC pipe holder + cut-down spring
Here's the math I've done for the build:
3 x 3.63v (Vf) x 0.7A (I) = 7.623W power output
7.623W / 0.9 (driver efficiency) = 8.47W power input
8.47W / 4.5v = 1.88A input current req'd from 3 D cells or
8.47W / 6.0v = 1.41A input current req'd from 4 C cells
So my question is how is the 1.88A drained from 3 D cells? e.g. does the driver drain 1.88A from each D cell, or does it drain 0.627A from each cell since it's running in series (1.88 / 3 = 0.627)? Also, how does the internal resistance of the alkaline chemistry affect this math?
I've looked at the Duracell Alkaline PDF spec sheets on discharge behavior so I know how the cells behave when drained at differing currents, but I need to know how much is being drained from them to figure out the rest of the math.
For those wondering why I'm using alkaline cells it is because this light is going to be for my dad and anything more complicated than loading a bunch of Duracells is not going to work (so no fancy Li-Ion or Ni-MH cell setups). The only thing I'm missing from that setup is the Fatman so I can change the driver selection of it'll make a difference, but I already have the rest of the parts and would like to finally put them to use before my T-bin lux3s become any more obselete.
Here's my proposed build setup:
Mag 3D
modamag PTS2-D
3x TX1K Lux3 stars
Fatman set for 700ma drive current
3x D cell alkalines or
4x C cell alkalines + PVC pipe holder + cut-down spring
Here's the math I've done for the build:
3 x 3.63v (Vf) x 0.7A (I) = 7.623W power output
7.623W / 0.9 (driver efficiency) = 8.47W power input
8.47W / 4.5v = 1.88A input current req'd from 3 D cells or
8.47W / 6.0v = 1.41A input current req'd from 4 C cells
So my question is how is the 1.88A drained from 3 D cells? e.g. does the driver drain 1.88A from each D cell, or does it drain 0.627A from each cell since it's running in series (1.88 / 3 = 0.627)? Also, how does the internal resistance of the alkaline chemistry affect this math?
I've looked at the Duracell Alkaline PDF spec sheets on discharge behavior so I know how the cells behave when drained at differing currents, but I need to know how much is being drained from them to figure out the rest of the math.
For those wondering why I'm using alkaline cells it is because this light is going to be for my dad and anything more complicated than loading a bunch of Duracells is not going to work (so no fancy Li-Ion or Ni-MH cell setups). The only thing I'm missing from that setup is the Fatman so I can change the driver selection of it'll make a difference, but I already have the rest of the parts and would like to finally put them to use before my T-bin lux3s become any more obselete.