D6 is just another diode to protect the entire LED string from reverse voltage. If the driver is hooked up backwards, D6 will carry the current, thereby limiting reverse voltage to probably under 0.5V.
I'm also going to hazard a guess that each LED is 4 dies in series, so total string voltage is ~60V. It's much easier to design a higher voltage, lower current driver than lower voltage, higher current one. I'm sure that's what was done here. That makes even more sense given the fact the rectified AC voltage is very high, so might as well take advantage of it. The only time it makes sense to go with a high current, low voltage system is when the raw supply voltage is limited, say because it's a battery-operated system.
D6 reverse-polarity makes sense and it's not a huge device so the low-current
high-voltage configuration makes sense. At 60v, current would be around 1.6A.
Doubtful D6 could carry 6-7A continuously for a high-current driver connected
in reverse, if it would allow such a low output voltage (almost a short).
Any idea about the smaller shunt diodes? The SIDAC idea is speculation. I
looked at specs for low-voltage part and at 1.6A its clamp voltage would still be
2-3v, which is a lot of power for a small device to handle indefinitely.
To the OP:
Do you have capability to do some simple testing: variable power supply, DMM,
various power resistors (or rely on current-limiting in the supply if available).
Also, you could run on lower current, lower brightness and probably slightly
higher efficacy, if you don't need 10k lumens. BTW you will need good heatsinking
as more than half the power you feed to it will go out as heat (at full current,
roughly 60W, think of an incandescent with that power).
Dave