I revitalized a "dead" 18650 - will it blow my house?

phlowcus

Newly Enlightened
Joined
Jun 8, 2009
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germany
So I had received a 2200mAh 18650 (as part of a mobile charger) which showed only 0,8V when I received it. I considered it dead, but in defiance of all good advices I tried revitalizing it. I took a 3,2V 16340 and connected it (with a DMM) in short batches of half a second to the 18650, the current flow was ~1A at start, ~20 seconds later it was about 0,1A until the cell voltage was 3,0xV.

I then charged it normally with 1A (under strict supervision), it didn't even get warm and acted just like a fresh cell. Also it seems to be able to hold voltage properly.

My question is... Is there any reason to mistrust the battery?
 
If you charge it up to 4.2V. Let it rest for a few hours, and recheck the voltage. If the voltage has dropped a lot... its probably and old cell and you should throw it away. If it voltage stays around 4.2V, its probably ok. The initial problem you had with the battery, could be due to pcb protection, rather than a faulty cell.
 
Hello Phlowcus,

When a Li-Ion cell sits in a over discharged state, the electrolyte and electrodes oxidize. A key factor is the amount of time spent at the low voltage.

This oxidation damages the cell. This damage shows up as a loss of capacity, and higher internal resistance. Higher internal resistance leads to increased cell heat during charging and use. Increased heat does its own damage and the result is lower capacity and higher internal resistance and the downward cycle continues.

When the damage proceeds at a uniform rate and with a uniform distribution, the cell simply wears out. The problem occurs when there is a localized "hot" spot. This can occur during charging or discharging, but seems to show up more often during charging. It may be better to say that it is observed more during charging, but keep in mind that most of the time it is difficult to monitor cells during use.

If the cell still has good capacity, holds voltage under load, and doesn't show an accelerated self discharge rate, it should be good to use.

There are variables in cells that make it difficult to determine how much damage they can take before they become distressed. We make general statements because all cells should perform well if their voltage is kept between 3.5 and 4.1 volts. It should be no surprise that there are exceptions to the general rules. It should also be no surprise that if you live in the area of exceptions, sometimes things will go wrong.

Another consideration is cost. If replacing the cell is beyond a persons means, they tend to accept higher risk and will use increased vigilance to offset the risk. On the other hand, others value peace of mind above the replacement cost of the cell. Still others will approach this as a "science experiment" and will endeavor to define the various shades of gray.

Tom
 
Hello Phlowcus,

When a Li-Ion cell sits in a over discharged state, the electrolyte and electrodes oxidize. A key factor is the amount of time spent at the low voltage.

This oxidation damages the cell. This damage shows up as a loss of capacity, and higher internal resistance. Higher internal resistance leads to increased cell heat during charging and use. Increased heat does its own damage and the result is lower capacity and higher internal resistance and the downward cycle continues.

Don't forget the copper dendrites! When you overdischarge a lithium-ion cell, the copper current collector for the negative electrode can oxidize and dissolve into the electrolyte. Upon subsequent recharging, the copper can replate in the separator and cause an internal short circuit. At best this is a performance problem, but at worst it is a big safety issue.

If it were me, I would not use any lithium-ion cell that spent a significant amount of time below 2V.

Cheers,
Battery Guy
 
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