Ok thanks for the info so far , i can not talk the moron language so we will have to use another :thinking:

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First if one is going to try to pass more than 1 amp through that silicon diode one would have to use a larger one , it looks like a 1 amper max , say a 3 amp just for a example , one could also wire all this up with the Mag in bits then if it works then a proper fitment would be needed (maybe enlarge the diode hole) as it is hard to see the size in the picture .
http://electronics.wikia.com/wiki/Rectifier_diode
It looks like the negative ring (
the one still on)is actually part of the body itself , correct?
And negative from the battery pack is just straight to the body?
Diodes are cheap , you'd have a parts shop around somewhere , radio-shack i have the impression is a general one over there , Schottky diodes are a few cents more than silicon , a 3amp for starters either silicon or the other type and a small one (1n9148)that is 500ma or so for the resistor one but both the same type , silicon might be easier for the moment , or pinch/rob them off a tv board or other circuit board , therefore FREE ! , a local tv repair shop would chuck out stuff.
The sliver/white band is the cathode end and is the represented line across the triangle in da quality drawing
😛 , look up/search diodes.
In the manual/specs for the smart-charger it might mention how much current is drawn to measure voltage , i'd guess it might be as low as 100ua maybe even lower , one would need to find out due to the resistance value would want to be calculated at a worst discharged battery voltage then use that + the ua the charger needs and in a calculator a value would pop out .
Or just try a 1k first just to see if the setup charges correctly , i assume you do have a multimeter? first then go from there , as this high resistance thing is all about limiting the current at the ring for shorting concerns and current if it does short , thats all.
Appy playing about 2nd2none :naughty:
ps-Actually just looking at the picture again before i clicked send , your picture is not clear which is the earth ring even though the diode is orientated the correct way for a "positive" .