LM317 question, regarding minimum voltage

Daravon

Newly Enlightened
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Nov 27, 2005
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I am following this mod with an LED I already have
http://www.candlepowerforums.com/vb/showthread.php?t=155553
and that LED is good for 1A, but I just measured my light and it's actually pulling 1.2A (3.5V V_f rather than 3.7 spec).

1. Is this really a big deal that is, is it going to burn my LED out real fast

2. I would like to use an LM317 as a constant current source, with a pot in the tailcap, for dimmage. But many websites like this recommend at least 2-3V across the LM317 for proper functioning. Since I have 4.5V from the batteries and 3.5v across the LED, will it work? Otherwise I could get dealextreme 3AA adaptors I guess.
 
Although you didn't specify which LED you're using, it's probably "good for 1A" assuming proper heatsinking. That mod has none. The LED will fry. I'd recommend a resistor of about 20-50Ω for extreme low output that will preserve the life of the LED (as well as give you a great long-running emergency light).

If you have your heart set on a dimmable, high-output LM317 build, you could build one of these, or I could build one for you.
 
I would like to use an LM317 as a constant current source, with a pot in the tailcap, for dimmage. But many websites like this recommend at least 2-3V across the LM317 for proper functioning. Since I have 4.5V from the batteries and 3.5v across the LED, will it work? Otherwise I could get dealextreme 3AA adaptors I guess.

I logged onto National's site to have a look... They have a graph on page 6 of their LM317's 28 page pdf called, "Dropout Voltage". At 25°C, the 1 amp I/O differential curve is just a hair over 2 volts. So your 3.5 vF LED requires at least a 5.5 volt source to drive it to 1 amp. Really you need a tiny bit more voltage for headroom. It means since current is everywhere the same in a series circuit, at 5.5 volts the LM317 will dissipate 2½ watts of power as heat. It's only a linear voltage regulator. You can wire the LED in series with a sense resistor and have the LM317 monitor the voltage drop to make it behave like a constant current regulator. But that will cost even more power loss at the sense resistor. I'm guessing you meant a 3D Mag like the post you linked to. If you use 3 of the 3*AA D cell adapters for a total of ≈10.8 volts, the regulator will use more power than the LED!:thumbsdow

TigerhawkT3 is right, unless you really need something for dimming, use a power resistor instead of an LM317. The only good thing is you can run down to any Radio Shack and buy a 276-1778 for $2.29. Other than that, something like the 5 mode 1,000ma AMC-7135 regulator from DX will only cost $3.19. Of course you will have to wait a month or so for shipping. These chips are also linear, but the pdf on them says their dropout is only 0.15 volts @ 350ma. There are three of them wired in parallel on the board. So you only need 3.65 volts for your particular LED to reach 1 amp. That would be perfect for 3 NiMH D cells.:thumbsup:
 
yup the LM317 is going to blow a lot of voltage out, when they have new mosfet low resistance stuff, and you arent connected to the wall socket :) no use blowing so much power out, unless you have the voltage to begin with, like a series setup.
 
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