By the way. How much voltage do you feed these PCB:s with? Is a single lithium 3.7v battery enough? or will it need more juice to produce 2.4mA?
Regards
Johan
the ones with that particular chip in them, current regulate by clipping and wasting the voltage that goes over what is needed to make it to the current (to drive the led) .
so say your LED Voltage (Vf) is at 3.7 (at the current) and your battery is at 4.0v these things will just burn up the extra power (so to speak) and keep the voltage right for the ammount of current.
so say your battery is at 3.5V , your led will be at or below that (due to the slight resistance of the curcuit) which means it will fall out of regulation, and Basically be Direct drive.
so its all about the voltage of your battery and the voltage your led runs at (when at that current).
when the battery is Above the LED voltage , it will clip it off to maintain the current , if its below that voltage it will do NOTHING but sit there basically
So in short, it is Resistance when the battery voltage is too high.
on MOST white led stuff this will mean when your battery is fully charged the LED will be at its full current, and as soon as the battery goes below about 3.6-3.9 the output will start to dwindle.
its a good "answer" to direct driving, without breaking something, but it will NOT boost the voltage when the battery goes to low.
so its all about the VOLTAGE of your LED at that amperage, and the battery voltage at that load.
because the 1xli-ion or 3xNimhy or 3xalkaline or 3x1.7v lithium is very CLOSE to the voltage of the leds were using, it clips great for those items.
and it will still clip well for 4x1.5v too, wasting a bit more, but staying in "regulation" longer.
but NOT for batteries over ~5.5volts (under load), because then it has to waste to much juice resisting, and the part will heat up.
it was best said once by a member here, its a Glorified resister

, it acts as needed ONLY when the voltage is TO HIGH for the LED (at that current level)