New Driverboard Schematic

Double_E

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Feb 8, 2005
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Does anybody know why a driverboard couldn't consist of a voltage dividing pot driving a transistor with a resistor defining maximum current in series with the current path of the transistor and the laser? I can't seem to figure out why it isn't done this way, since it would be inexpensive and be able to handle a lot of power. The control of the pot might not be linear, but it would still work right?

Thanks for any help!
 
You can only cnage the voltage with the pot. But a Laserdiode needs constant Voltage and adjustable Current
 
The current defining resistor should be small so as to drop less voltage(say <0.1V) to maximize the efficiency. Therefore, a simple transistor current regulator is not good enough.
 
How can you have a constant voltage with adjustable current? Current and voltage are related to eachother linearly. I don't think you can change the current through the laser diode without changing the voltage across it at the same time. Could you give me a more in-depth expaination arni? Thank you for your help.
 
Hi double E,
Use google and read up on ohm's law and also on op amp circuits, current and voltage sources.

Jack
 
The output of a diode is determined by the current through it, the current through it is determined by the series resistance that limits it. Tell me what is wrong with that statement? I know we want a constant current source, but since that is a ficticious device, we have to apply vary the voltage across the diode-resistor path. Once it is set how we want it, it doesn't have to change.
 
Voltage = current x resistance
Current = voltage / resistance
Resistance = Voltage / Current

There will be a test at the end of the marking period.
Failure will result in detention.
 
Is there anybody who is actually familiar with electronics and the driver circuits who can tell me why we can't just use a pot to bias a transistor like a 2222 to run the laser diode with a current limiting resistor in series? Thanks
 
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