Re: The Real Reason for Throw-an in depth examination
Distance as it relates to reflectors
IMHO the OP has explained this nicely.
Still there appears to be confusion regarding this concept which I think may be arising from the 2nd paragraph about "Distance as it relates to reflectors" (in Post #1), This is a little harder to visualize...
saabluster:
So you want to know what part of the projected beam consists of what images? Let's start in the center of the projected beam or the beam you would see on a white wall at 20 feet or so(beam has to have space to mature). The most intense round spot you see is mostly what has been reflected by the outer area of the reflector. It also consists of the less intense and larger images created by the lower portions of the reflector. So all of the reflector contributes to the center of the projected beam but the outer portions of the reflector do not add any intensity to the outer areas of the projected beam.
I'm guessing the OP may have planned to explain this further but I think the following may be helpful to understand what OP is saying.
As usual, a simpleton like me, believes we are dealing with too many complex factors here: reflection, multiple angles/surfaces of reflection, focal points, emitter sizes, intensity, etc, etc.
Allow me to attempt to simplify things so just momentarily, lets forget these complex factors and come back to the one basic optic principle
The Law of Reflection
Angle of incidence equals angle of reflection
If you can grasp this very simple concept, the more complex mystery about why the outer part of a reflector is able to create the more intense area of a hotspot/beam, will very shortly reveal itself to you.
DIAGRAM 1 (below)
ok this is self explanatory, no mystery here right?
DIAGRAM 2 (below)
If we measure the size of the reflected images at 1 meter from the reflector,
you will see that the further away the source image (or emitter) is, the smaller the size of the reflected angle and reflected image.
Still with me?
Ok, now in Diagram 3, we see how this relates to flashlights.
DIAGRAM 3 (below)
Now in diagram 3, I have added a multi-angled reflector (simulating the shape of one in a flashlight). The multi-angled reflector helps to guide the reflected beams into a more useable pattern (or what we might call beam profile).
I am simulating 2 reflections/beam patterns from the emitter source.
A) a reflection at an area in the center of the reflector & very close to the emitter.
B) a reflection at an area towards the outside of the reflector & further away from the emitter.
Can you see which part of the reflector causes flood/spill and which part causes the hotspot in this example?
So now we can see the relationship between emitter distance to different parts of the reflector.
As a bonus,
we have also
just uncovered the mystery of surface brightness 🙂
Just as distance to reflector reduces the "reflection angle", a smaller image will also reduce reflection angle.
DIAGRAM 4 (below)
Notice how the smaller source image creates a smaller reflection (and reflection angle)?
This means that if both source images (emitters) were to have an equal TOTAL lumen output (eg. both 500 lumen emitters), the reflected beam from the larger (A) source image will be wider (floodier) and the reflected beam from the smaller (B) source image will be narrower (tighter aka more throwy)
Additional Note:
For further clarity still, imagine in the Diagram 4 example that:
the larger emitter has a surface area of 5mm square (100 lumen per square millimeter)
the smaller emitter has a surface area of 1mm square (500 lumen per square millimeter)
We now get 500 lumens of output from each beam, yet comparing both beams,
one appears floody and one appears much brighter and tighter.
END
I hope that wasn't too long ...
Saablaster > as always, feedback most welcomed (and of course goes for all CPF'ers). Happy to remove/edit anything that is not appropriate.
tgwnn