Hello, i opened both lights and the circuit is the same:C300-AL5W : in the QIII with a R015 ohm resistor (on 1 123cel) and in the 301X5 with a R030 (on 2 123cells).
On the QIII i measure 0.800A on the battery=0.8x3V=2.4W for the luxIII-some losses in the circuitboard (30%?)= +-1.7W output?
On the 301X5 i measure 0.700A on (2) batterys=0.7x6V=4.2W for the luxV-some losses in the circuitboard (30%?)= +-2.95W output?
So can i replace the luxV in the 301X5 with a luxIII or will it burn out (led)?
Or can i replace the resistor in the QIII , so that the luxIII is driven at 800mA (3Watts)?
Thanks Marc
On the QIII i measure 0.800A on the battery=0.8x3V=2.4W for the luxIII-some losses in the circuitboard (30%?)= +-1.7W output?
On the 301X5 i measure 0.700A on (2) batterys=0.7x6V=4.2W for the luxV-some losses in the circuitboard (30%?)= +-2.95W output?
So can i replace the luxV in the 301X5 with a luxIII or will it burn out (led)?
Or can i replace the resistor in the QIII , so that the luxIII is driven at 800mA (3Watts)?
Thanks Marc