Raven said:
I'd like to see Fenix sell a 5w that uses aa batteries, and I'm curious how many you'd need to get both decent output and a flat 2 hour runtime.
According to Sanyo, you can get pretty close to the rated capacity at up to "C" rate.
Their 2.5Ah cell is rated at "2.3Ah minimum" capacity, so we'll calculate around 2.2Ah.
You will need six cells and a buck/boost converter, because the forward voltage of Luxeon V is around 6.5v(average) and six cells in series start off around 7.8v and ends at 5.5-6.0v
Assume 75% efficiency.
5watt/0.75 = 6.67watt
nominal voltage = 7.5v
6.67w/7.5v = 0.89A (increases to 1.21A near the end as battery drops in voltage)
2.2Ah/0.89A =2.47 ~ 2:30 hours. The regulator reduce the LED drive current to 25% or less once battery voltage drops to 1v/cell and shut down at 0.9v/cell to avoid polarity reversal damage to batteries.
8-10 alkaline AAs should work as well, but at the rate of five alkaline batteries per hour, its gonna get kinda expensive...