Doug S
Flashlight Enthusiast
I am amazed with the amount of innovative work with Luxeons that is being done by the some of the more serious moders here. I am pleased that so many take the time to share what they are doing. I do experience disappointment, however, when I see someone who obviously put much thought and effort into a creative mod but their own analysis of their work is in the vein of "its brighter than my XXX and is not so hot that I have to drop it".
I want to encourage the *serious* moders to instrument their mods. With only a tiny hole for very fine wires [that can be later plugged if desired] it is fairly easy to measure actual LED voltage, current, and heat sink temperature. From these data, actual junction temperature is easily calculated.
How to do it:
Voltage: obvious
Current: I recommend using a 0.1 ohm sense resistor in the LED circuit. This is low enough to have negligible influence on the circuit yet will provide 1mA resolution when measured on the 200mV scale of the typical 3 1/2 digit DMM [100mV = 1A]. The price of low-ohm sense resistors has dropped in the past year. At Digikey you can get 0.10 ohm, 1%, 0805 SMT package ones of 10/$3.44. On a Luxeon Star, it is easy to cut one of the power traces with a Dremal type tool and then bridge the cut trace with the sense resistor.
Temperature: National Semiconductor make a number of three terminal temperature sensing ICs. These include the LM20, LM34, LM35, LM45, LM50, LM60, and LM61. For our uses, the LM61 is the best bet. It can be had for about $1/each at Digikey.
See link
http://www.national.com/pf/LM/LM61.html
It is available in both SOT-23 and TO-92 packages and has a low enough operating voltage to power directly from the voltage applied to the LED. Current consumption is a negligible 100uA. I strongly recommend the SOT-23 package because it thermally couples much better to the surface it is mounted on than the TO-92. In the case of the Luxeon Star, the V+ and GRD pins of the SOT-23 will span the (+) and (-) pads of the Luxeon thus providing a good measure of the PCB temperature.
So what can you do with the data obtained?
First, and foremost, you can impress your CRF buddies.
Here is an example of data usage: You have instrumented you new XYZ mod as recommended and obtain the following data; Vled=3.31V, Iled=380mA, temp=98C. You can calculate power, P=(3.31V)x(.38A)=1.26W. Now, from the datasheet, the junction to PCB thermal resistance is 17C/W so now you can calculate the actual junction temperature as 98C + (1.26W)x(17C/W) = 98+21.4=119.4C.
OK, so what if you don't think that your mods are in the same league as, say, dat2zip? You can play too. Suppose your mod is simply N-cells driving a Luxeon through a dropping resistor? With 3 tiny wires you can bring out the LED voltage, the battery voltage, and the drop across the dropping resistor. With this information, you can measure/calculate actual LED voltage, current and power. Example, you are using a 2 ohm dropping resistor. You measure Vled=3.2V and Vres=.58V. To get LED current, use ohms law I=E/R =.58V/2ohm=.29A. Now you can calculate LED power = (3.2V)x(.29A)= 0.93W. With your instrumented light, you can actually measure what happens to LED current as the batteries run down instead of guessing. You will also gain an appreciation of just how much light Luxeons can put out at very low current levels. You can also step forward and answer the [seemingly endless] questions that appear on the board "how much current will a Luxeon draw on 3 C cells?" You can say... I don't know about your particular sample but mine draws xxx under the following conditions...
I want to encourage the *serious* moders to instrument their mods. With only a tiny hole for very fine wires [that can be later plugged if desired] it is fairly easy to measure actual LED voltage, current, and heat sink temperature. From these data, actual junction temperature is easily calculated.
How to do it:
Voltage: obvious
Current: I recommend using a 0.1 ohm sense resistor in the LED circuit. This is low enough to have negligible influence on the circuit yet will provide 1mA resolution when measured on the 200mV scale of the typical 3 1/2 digit DMM [100mV = 1A]. The price of low-ohm sense resistors has dropped in the past year. At Digikey you can get 0.10 ohm, 1%, 0805 SMT package ones of 10/$3.44. On a Luxeon Star, it is easy to cut one of the power traces with a Dremal type tool and then bridge the cut trace with the sense resistor.
Temperature: National Semiconductor make a number of three terminal temperature sensing ICs. These include the LM20, LM34, LM35, LM45, LM50, LM60, and LM61. For our uses, the LM61 is the best bet. It can be had for about $1/each at Digikey.
See link
http://www.national.com/pf/LM/LM61.html
It is available in both SOT-23 and TO-92 packages and has a low enough operating voltage to power directly from the voltage applied to the LED. Current consumption is a negligible 100uA. I strongly recommend the SOT-23 package because it thermally couples much better to the surface it is mounted on than the TO-92. In the case of the Luxeon Star, the V+ and GRD pins of the SOT-23 will span the (+) and (-) pads of the Luxeon thus providing a good measure of the PCB temperature.
So what can you do with the data obtained?
First, and foremost, you can impress your CRF buddies.
Here is an example of data usage: You have instrumented you new XYZ mod as recommended and obtain the following data; Vled=3.31V, Iled=380mA, temp=98C. You can calculate power, P=(3.31V)x(.38A)=1.26W. Now, from the datasheet, the junction to PCB thermal resistance is 17C/W so now you can calculate the actual junction temperature as 98C + (1.26W)x(17C/W) = 98+21.4=119.4C.
OK, so what if you don't think that your mods are in the same league as, say, dat2zip? You can play too. Suppose your mod is simply N-cells driving a Luxeon through a dropping resistor? With 3 tiny wires you can bring out the LED voltage, the battery voltage, and the drop across the dropping resistor. With this information, you can measure/calculate actual LED voltage, current and power. Example, you are using a 2 ohm dropping resistor. You measure Vled=3.2V and Vres=.58V. To get LED current, use ohms law I=E/R =.58V/2ohm=.29A. Now you can calculate LED power = (3.2V)x(.29A)= 0.93W. With your instrumented light, you can actually measure what happens to LED current as the batteries run down instead of guessing. You will also gain an appreciation of just how much light Luxeons can put out at very low current levels. You can also step forward and answer the [seemingly endless] questions that appear on the board "how much current will a Luxeon draw on 3 C cells?" You can say... I don't know about your particular sample but mine draws xxx under the following conditions...