cordless phone battery driving CREE?

i want to make something of my broken coleman 2aa max. I have a 3.6v cordless phone battery (tested fully charged at 3.8) and want to use it for direct driving the CREE. will 3.6v 800 mah be too much for the LED, or will it work? it currently has a driver circuit (step up from 3v-3.6) that is functional. i have tested the cree with this battery, and it has worked, but i want your guyses oppionion before i do some soldering.
Edit: also since there is a driver, can i mod this into my 2d mag, or will the current fry the driver?

Should be fine running the cree with the driver in the 2d mag if you can mechanically get it in there. I'd be leary of connecting the driver to a 3.6v rechargeable battery. Fully charged that battery should be more like 4.3 volts. If the driver was strictly designed for 2AA batterys there may be a problem. Probably some experts here who have hacked a coleman lantern could tell you for sure.

oh i ment for the 3.6 v battery for directg drive, no driver, but i would figure it would fry the driver if i tried to run it off d's. so whens your funeral holepuncher?:laughing:

Well hopefully my funeral wont be for at least 20 years but I'm sinking fast into flashaholism and doing crazy things so it may be sooner.

You should have no problem direct driving the LED from your 3.6 volt battery assuming the led is rated for at least a couple of watts and is on a star board. If you run the driver/led from 2 d's there should be no problem.

i wanted to do this with a few smd leds on my i560 direct run off the phone battery,

just tested it, but the pill got uncomfortly hot in 20 seconds, so i think ill just use it with the phone battery.

rockz4532 said:

will 3.6v 800 mah be too much for the LED

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Are you confusing mA with mAh?

shadowjk said:

Are you confusing mA with mAh?

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im not much of an electrics person, but whatever is measured on a battery is what im talking about

mA is the current delivered to the LED, mAh is the capacity of the battery.

mAh has very little to do with what current the LED sees.