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StoneDog said:
I wonder if I can safely extrapolate from these numbers what my F ranked amber will do...
If H Vf is nominally 3.1 and F Vf is nominally 2.6, there should be a .5 volt difference in their forward voltages when running at spec.
If we then assume (probably incorrectly?) that 3 volts Vin to an F ranked amber luxeon is equivalent to 3.5 volts Vin to an H ranked R/O luxeon, then I will end up driving the amber somewhere between 620ma and 750ma. /ubbthreads/images/graemlins/icon3.gif
Shouldn't an H Vf luxeon be pulling somewhere between 350 and 400 ma at 3 volts? By your numbers that R/O is actually a high G?
Jon
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Except that your battery's terminal voltage will drop with increasing current, due to the internal resistance of the battery. A lithium 123 cell has about 0.25 ohms of internal resistance. This will cause the battery voltage to drop under load, reducing the current.
Let's assume an 0.5V lower Vf (which we don't know, it's pure speculation until you actually measure the Vf at 350mA), and say it gives about 700mA. You must now see if that's possible given the battery's internal resistance.
At 700mA, the battery's terminal voltage will drop to about 2.8V. But we've assumed that the Vf was 3.0V, so that solution is no good. Vbatt must equal Vf in DD. I'll guess that the real solution gives you about 500mA current.
However, it is quite likely that the Vf of your amber is near the high end of the Vf range, so even with the lower binned Vf, I'll still say it will be around 500mA or lower. Best way to find out is to use a DMM to measure the current from a 123 cell in DD. Only test for a couple seconds just in case.