Okay, there's got to be someone here who's taken a math class in the last millenium. I've already forgotten what little I used to know about it in the first place. Here's the problem
I need to find the equation of a circle given 2 points (x1, y1) and (x2,y2), plus the Radius (R) and the angle between the two points (theta)
the equation would look like this
(x - x0)^2 + (y - y0)^2 = R^2
where y0 and x0 are the center of the circle
All I remember how to do is calculate the equation given 3 points, but not 2 and the angle.
My goal is to find the location of any point on that circle in cartesian coordinates, given a different theta, so ideally I'd want the solution to look like
x = f(x1, x2, y1, y2, R, theta)
y = f(x1, x2, y1, y2, R, theta)
I know there are two real solutions to this problem, the center will lie on the line bisecting the line between the two points. I also know the direction of rotation of theta, so that should be able to narrow it down to a single solution. Please help, all my math books have disenegrated from old age.
I need to find the equation of a circle given 2 points (x1, y1) and (x2,y2), plus the Radius (R) and the angle between the two points (theta)
the equation would look like this
(x - x0)^2 + (y - y0)^2 = R^2
where y0 and x0 are the center of the circle
All I remember how to do is calculate the equation given 3 points, but not 2 and the angle.
My goal is to find the location of any point on that circle in cartesian coordinates, given a different theta, so ideally I'd want the solution to look like
x = f(x1, x2, y1, y2, R, theta)
y = f(x1, x2, y1, y2, R, theta)
I know there are two real solutions to this problem, the center will lie on the line bisecting the line between the two points. I also know the direction of rotation of theta, so that should be able to narrow it down to a single solution. Please help, all my math books have disenegrated from old age.