picard said:
How many CR123A batteries will be needed if one holds out in houston for 12days using 2 battery LED flashligh such as gladius or PM6 3watt ? I am curious if anyone has experience with this scenario.
I don't have experience with precisely that, but I can tell you what I would do.
I would want the minimum capability to have light for 50% of all dark hours, with say 25% of flashlight use being on a bright setting.
Let's say the light is my SureFire L2: 1 hour runtime on bright and 12 hrs on low. I am not familiar with the others' runtimes.
The total time when the light will be on (50% of all dark hours) would be half of 12 days at 12 hours per night. That's 6 hrs per night for 12 nights -- 72 hours total. 25% of that is bright -- 18 hrs high beam. 75% is dim -- 54 hrs low beam.
In order to do the 18 hours of bright, you need 18 complete changes of batteries -- at two batts each that's 36 batts for bright use.
For the dim use you will need 4.5 changes (54 hours divided by 12 hrs per change equals 4.5 changes. So that's another 9 batteries. Make it 10 because they have to be used in multiples of 2.
So there you go. Your nearly 2 weeks of no power requires 46 lithium primary cells. You would buy 4 boxes of 12 from SureFire for $15 ea. for a total of $60 for 48 batteries before shipping.
If you used only the low beam of the L2 you would get 12 hrs per change for the whole 72 hrs of light time, then you need 6 changes or 12 batts -- only one box.
I think if you were a rescuer or law enforcement officer, you'd use a whole lot more than that (mostly because you need a lot of bright time for that work). Probably the average homeowner would use less. Figure half a box for the homeowner and 6-10 boxes for the rescuer/LEO.
Scott