Why?
(That Energizer Max doesn't do too well compared to the others.)
Within a handful of minutes the cells are down to 1.4V, and by the time they hit 1.2V there's, what? 75-80% of the life left. And even 3x1.2 V would be enough only if the Vf of the LED is <=3.4V. Yeah, they exist in quite a few P4s, but I don't think many Q5s. From 1.2V onward, even a 3.4 Vf LED would be out of regulation.
I still say three alkaline cells are not suited for this driver (unless you want to just use the top 20% of each cell's capacity).
mike2g, your point of voltage difference is very good. I'll still say 4 alkaline cells will work quite nicely, though, with a qualifier or two. Because of the way alkaline cells discharge, the board when used with the LED tested above would be in the higher efficiency area (median would be 84.5%) for four times longer than it would be in the low efficiency area. So for efficiency, it would work nicely. If regulation is your goal, however, you'll have to use a low Vf LED to have it stay in regulation until 0.8 V per cell, and that would push the median efficiency down (to ~75%), which I'd still be happy with for efficiency as well. I don't deny you might have trouble finding the right LED though.
That's a contradiction. I suppose the efficiency area isn't quite a subset of the regulated area, so you could say the areas are in different, but not separate, places.
It's a great test, and both very interesting and very useful, but meticulous probably means something other than what you intend. You can't have 1.24 A in and 1.28 A out with a linear regulator - no disrespect intended to you Drewfus.
(Actually, one definition for meticulous I found is "ridiculously obsessed with extreme minutiae" - which would be me posting this.
)
freedom2000, I don't think such a driver exists, if $20 (for a GD1000) doesn't come into your idea of cheap. Have you seen the
driver list?