Is the offered level equivalent to the current #8? or dialed back a bit?
I recall you saying the QTC reduces the voltage, not the current. I'm assuming then, that even when using the lower output, there will be no change in runtime? would the draw need to be greater due to the boost circuit?
I recall you saying the QTC reduces the voltage, not the current. I'm assuming then, that even when using the lower output, there will be no change in runtime? would the draw need to be greater due to the boost circuit?