Ok, lets talk about calculating Candela/lux. It much easier than you think.
I will show you a formula for calculating maximum center-beam Lux for any light with a lightsource and a reflector or optic. All you need is the diameter of the reflector/optic and the luminance of the light source.
Lets use your 100mm lens and a Cree XP-G2 as an example. Luminance values for the XP-G2 can be found in different threads in the German TLF Forum (sorry, no English, just use google translate).
Here you can find a luminance values of many different LEDS (measured) and many other lightsources. TLF-member sma is an expert on this subject and has gone to painstaking effort to measure theses values as accurately as possible for him. You can see there that a Cree XP-G2 R5 mounted on copper "DTP" PCB will reach a maximum of 200cd/mm^2 under ideal conditions. The problem with this LED is that Cree increased the size of the DIE twice last year (see
here). The larger the DIE, the smaller the luminance (unless there are much more lumens emitted from the larger DIE). The old R5 and S2 LEDs had the small DIE. Then came the S3 and S4 Bins which probably were one size larger. Later on Cree made the DIE bigger again. This is the size of the current S4-binned XP-G2s (and the luminance is probably not as high as before).
Here is a measurement of a larger S4-binned emitter, probably the medium sized DIE. It's still quite good. Now wee want to find out how the luminance changes with the Wavien colar. sma also studied and measured this
here (he used an old-style XP-G2 S2 and all three collar sizes). Generally at the maximum possible current and perfect focussing (very difficult with the Wavien collar) you can expect up to 2.2x the luminance (which is amazing). He measured 470cd/mm^2 @ 6A. I will use this value for my calculation.
Imagine that you are looking at the optic your light from where the hotspot would be. From this perspective the reflector/optic looks like a flat circle. We now need to calculate the area of the circle that is lit up by the LED (the part that is yellow). For a 100mm diameter lens, this is (50mm)^2*pi = 7854mm^2. Now all you have to do is multiply this with the luminance of your LED and subtract some losses.
Luminous intensity = luminance * surface_area_of_optic * losses_lens_transmission * losses_because_of_heat
= 470cd/mm^2 * 7854mm^2 * 0.92 * 0.95
= 3226266cd = 3.23Mcd
So if there are no substantial problems with your light and you are using a "good" XP-G2 @ 6A with an optimally placed collar and the 100mm fasttech lens is lit up completely by the LED, you should be getting 3 Million Candela.
Details on the formula I used can be found
here. The well known DrJones might also have an English explanation on his website, but I am not able to open it.