8AA in serial + parallel = 6 volts?

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Suppose you filled a Mag 2D with 8AAs at 1.5 volts each.

Now suppose you packaged four of them in serial at 1.5 + 1.5 + 1.5 + 1.5 = 6 volts.

Now suppose you packaged the other four of them in serial at 1.5 + 1.5 + 1.5 + 1.5 = 6 volts.

Now suppose you connected those two packages in parallel to deliver 6 volts to the bulb.

Would this give twice the mAh (and battery life) at 6 volts as 4AA's at 6 volts?

Possible? Good? Thoughts?
 
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I'm looking at bulb options (post 4):


...and trying to get the most run time and reliability out of the GH24, residing in a 2D, powered with something like:



I started off looking at the standard overdriven 5-7 cell configs (+ 1-3 dummy cells), but why not fill it up with 8 full cells at 6 volts. This is for a rare use automotive light that would be filled with lithium AAs.

2900mAh x 8 = 23200mAh​
 
I'm looking at bulb options (post 4):
...and trying to get the most run time and reliability out of the GH24, residing in a 2D, powered with something like:
I started off looking at the standard overdriven 5-7 cell configs (+ 1-3 dummy cells), but why not fill it up with 8 full cells at 6 volts. This is for a rare use automotive light that would be filled with lithium AAs.
2900mAh x 8 = 23200mAh​

Lithium AAs are closer to 1.7V I believe and you wouldn't get 23200mAh at 6V. You don't add the capacity unless you are connecting in parallel. Series adds voltage where as parallel adds capacity. What you would get is 2900mAh X 2 at 6Vish.
 
Be Careful / Re: 8AA in serial + parallel = 6 volts?

Please, be very careful when using such a battery array :

In practice, due to voltage differences between the battery packages, current will circulate through them even under no load conditions, which might give you unpleasant and risky surprises (reverse polarity, batts overheating, venting, leaking, explosion).

The proposed battery array will expose you to the same dangerous conditions of mixing fresh and depleted cells.

Take care
 
The Princeton Tec "Surge" uses this configuration.
 
Thanks for the information. You are absolutely right.

Do you know if the power switch or circuitry in the Princeton Tec Surge use diode protection or maybe disconnect the parallel batt banks when the flashlight is not in use ?

Otherwise, the user must extreme precaution in using matched pairs of batteries by checking them with a DMM.
 
I would not use 1.5 Alk AA's. I use rechargeable NiMH, so 1.2V x 6=7.2V And if you need more run time, carry an extra set.
 
Thought: If you're going to be using lithium AAs you could better afford the ~0.6V drop that diode protection would take.
 
Thought: If you're going to be using lithium AAs you could better afford the ~0.6V drop that diode protection would take.

Apparently I chose the wrong moniker. Would you mind explaining how a diode works and what it does for this application?
 
Apparently I chose the wrong moniker. Would you mind explaining how a diode works and what it does for this application?

A diode is an electronic component that only allows current to flow in one direction. In this application I believe that it would prevent differences in potential from trying to flow current in wrong direction (effectively trying to charge the battery).
 
A diode is an electronic component that only allows current to flow in one direction. In this application I believe that it would prevent differences in potential from trying to flow current in wrong direction (effectively trying to charge the battery).
Yes indeed. And with the slightly higher voltage of lithium AAs - and their lower voltage drop under load - you'll have more spare volts to do that with. But I'm not sure it would really be necessary if you had reasonably well matched cells to start with.
 
im not familiar with the protection diode but it is not recommended to leave the connection in parallel when not in use. I've done it before and after a while, the batteries became very hot.

i could guess that the side which has the lower voltage is getting charged up by the side with the higher voltage.. and this goes on and on til the batteries die out since its hard to reach an equilibrium voltage between the two..
 
im not familiar with the protection diode but it is not recommended to leave the connection in parallel when not in use. I've done it before and after a while, the batteries became very hot.

i could guess that the side which has the lower voltage is getting charged up by the side with the higher voltage.. and this goes on and on til the batteries die out since its hard to reach an equilibrium voltage between the two..

That's why you put a diode in the direction of current flow at each end. Like this.

diodeprotectioncircuit.jpg
 
great idea, the diode would prevent any cross charging of cells.

with a HIGH load device an tiny bits of resistance due to the number of connections that exist you could indeed end up with a parellel imbalance.

usually the loads are so minimal that parellel imbalance is not an issue, but if your doing crasy drain a battery applications with hotwires, and the batteries are not Soldered or Tabbed, in with fat copper and all, it certannly could become an issue. even a holder spring can have more resistance than one would expect when used with high amperages.
it would depend a lot on the application, and when the application is some AA holder thing and a HOT incan bulb then it would be an application where it would be concidered.

a parellel imbalance wouldnt be a big issue with ni-??? but it would be with Primary cells that do not intend to be charged in any way shape or form, especially lithium primaries.

there are "shotkey" diodes that are 1/2 the voltage drop at about .3V drop, not only do they drop less, but BECAUSE they drop less there is less heat dissipation needed to keep the diode from overheating.

then there is a Trick you can do with a MOSFET, that has almost 0 resistance , you turn a mosfet into a diode by how you wire it, and it requires gate voltage to stay open. i dont quite understand how exactally, only did it once but its one way to have diode like protection with about .01-.001ohm resistance AS LONG AS you have the voltage for the gate, which could come in handy as a low volt cutoff, or terrible (also) as the mosfet became higher in resistance (heat).

if somone was whining about the waste or voltage losses, they could look into how to make a mosfet work like a diode in that particualr application (for that application because of the mosfets gate voltage)
 
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That's why you put a diode in the direction of current flow at each end. Like this.
Nice diagram. I took apart a Stanley 6 LED tripod torch - with 3 cells in each leg - and found that's what they use there as well (followed up by a fancy control circuit).

FYI http://en.wikipedia.org/wiki/Schottky_diode - it mentions the MOSFET solution, too. There was a thread I was participating in about 7 months ago where we were talking about that sort of thing, but sufficiently good MOSFETS here are horrendously expensive.
 
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Absolutely awesome, thanks everyone!

Makes me wonder if the 750 -> 1500 amp dual battery setup in my truck would benefit from something like this. A solenoid isolates them when idle, but they do seem to die more often than they should. :confused:

Word from the Sandwich shoppe came down today, my 8AA pack shipped. It may not be possible to add a pair of diodes, but I'll have a look. I'm also going to try 12 volt bulbs:

http://www.candlepowerforums.com/vb/showthread.php?t=176519
 

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