Illum
Flashaholic
Several DC/DC switching regulators have this function, namely the presence of "LBO" and "LBI" pins. I'm in the process of coming up with a stable circuit for the LT1308 Chip :grin2:
Info here: http://cds.linear.com/docs/Datasheet/1308abfb.pdf
I'm trying to build a portable battery pack that can provide 5V output for charging gadgets on the go.
So far, it looks something like this: :rolleyes:
[USB Male] ---> [MAX1811] ---> [AW 18650] ---> [LT1308] ---> [USB Female]
In the past I've largely ignored this "Low Battery Detection" feature because I was using primarily NIMH and battery packs far bigger than any practical charge time would require. However, lately after seeing the ECOSOL Powershot I've been wondering to myself if I have the potential to come up with my own pocket charger. :ohgeez:
Here's the block diagram of the LT1308 :eek:
According to the pin functions, the SHDN pin turns the device off when pulled low to ground.
The datasheet states that:
As far as the block diagram shows, in the heart of the comparator there lies an NPN switch that pulls LBO low as long as LBI > 200mV, turning off only when LBO </= to 200mV. If the logic is correct, then my wiring goes as follows:
Suppose I want this to lock out at Vbat: 3V, LBI = 0.2V, R1 = 130K, R2 = 10K is a good starting point. As long as LBI > REF, SHDN transistor pulled low, keeping the NPN off. While potential of at least 1V maintained at SHDN by means of a pull up [~1K?]. When comparator turns off, the pull up resistor at the base of the SHDN pin's NPN turns it on, which causes the IC to shutdown, drawing only 1uA at the chip and whatever the pull-up will eat.... so it can't be drawing only 1uA in shutdown mode!
Obviously I'm not doing something right, because down in the middle there's this:
Okay... now I'm totally lost :shrug:
What is "To processor?" and pull up from 5V... that an external reference or is that supposed to be Vout?
R1 = [VLB - 200mV]/2uA... err, when I see that I think of [VLB - 0.2V]/0.000002A... Assuming R2 = 100K and VLB = 3V, R1 would compute to about 1.4M, gee... that seems a little high.
Am I even looking at this correctly? Please :help:
:thanks:
Info here: http://cds.linear.com/docs/Datasheet/1308abfb.pdf
I'm trying to build a portable battery pack that can provide 5V output for charging gadgets on the go.
So far, it looks something like this: :rolleyes:
[USB Male] ---> [MAX1811] ---> [AW 18650] ---> [LT1308] ---> [USB Female]
In the past I've largely ignored this "Low Battery Detection" feature because I was using primarily NIMH and battery packs far bigger than any practical charge time would require. However, lately after seeing the ECOSOL Powershot I've been wondering to myself if I have the potential to come up with my own pocket charger. :ohgeez:
Here's the block diagram of the LT1308 :eek:
According to the pin functions, the SHDN pin turns the device off when pulled low to ground.
The datasheet states that:
Linear said:The LT1308A/LT1308B low-battery detector is a simple PNP input gain stage with an open-collector NPN output. The negative input of the gain stage is tied internally to a 200mV reference. The positive input is the LBI pin. Arrangement as a low-battery detector is straightforward.
As far as the block diagram shows, in the heart of the comparator there lies an NPN switch that pulls LBO low as long as LBI > 200mV, turning off only when LBO </= to 200mV. If the logic is correct, then my wiring goes as follows:
Suppose I want this to lock out at Vbat: 3V, LBI = 0.2V, R1 = 130K, R2 = 10K is a good starting point. As long as LBI > REF, SHDN transistor pulled low, keeping the NPN off. While potential of at least 1V maintained at SHDN by means of a pull up [~1K?]. When comparator turns off, the pull up resistor at the base of the SHDN pin's NPN turns it on, which causes the IC to shutdown, drawing only 1uA at the chip and whatever the pull-up will eat.... so it can't be drawing only 1uA in shutdown mode!
Obviously I'm not doing something right, because down in the middle there's this:
Okay... now I'm totally lost :shrug:
What is "To processor?" and pull up from 5V... that an external reference or is that supposed to be Vout?
R1 = [VLB - 200mV]/2uA... err, when I see that I think of [VLB - 0.2V]/0.000002A... Assuming R2 = 100K and VLB = 3V, R1 would compute to about 1.4M, gee... that seems a little high.
Am I even looking at this correctly? Please :help:
:thanks:
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