HERE Is a thread about the Cree Q4. I am guessing the Vf of the q5 will be slightly lower and the output perhaps 5-10% more so
I am guessing at 350ma you will get about 120 lumens out of a q5 by the charts that is perhaps the output of a ~10-20 watt incan bulb?
ok I am guessing 3.4v is needed so 3nimh is charged about 4.2v so you need to drop 0.8v at 350ma.
using ohms law E=IR or R=E/I we get 0.8/0.35 or 2.3 ohms. using P=IE (watts law) P (power in watts) is 0.8x0.35 or .28 watts... a half watt resistor I think should suffice at that level. I am rather tired so if my math is off don't get too upset
try a 5 ohm then work down to a 2 ohm with the 10A ammeter inline while going. if the current exceeds the 350ma by much your Vf may be lower or batteries could have more charge voltage.
I am guessing at 350ma you will get about 120 lumens out of a q5 by the charts that is perhaps the output of a ~10-20 watt incan bulb?
ok I am guessing 3.4v is needed so 3nimh is charged about 4.2v so you need to drop 0.8v at 350ma.
using ohms law E=IR or R=E/I we get 0.8/0.35 or 2.3 ohms. using P=IE (watts law) P (power in watts) is 0.8x0.35 or .28 watts... a half watt resistor I think should suffice at that level. I am rather tired so if my math is off don't get too upset
try a 5 ohm then work down to a 2 ohm with the 10A ammeter inline while going. if the current exceeds the 350ma by much your Vf may be lower or batteries could have more charge voltage.
Last edited: