Ok, hmmm...
Mr Al: That's about what I had thought too, but wanted a second opinion.
As for input voltage. That is TBD, since I need to figure out what will work with it. I was thinking that it would be optimal if I could do it off of 2x123 (3 volts apiece for 6 total), or perhaps 3 D cells (1.4-1.6v a piece for 4.2-4.8 volts total). I know 123's should be able to supply that much current, and I just measured a fresh D cell at 1.866 amps output, so it should be OK for that too, at least for a while. The beauty of using a circuit like this is that you could exchange bodies and use more cells without any circuit modification necessary.
Package size should be no problem, since I have successfully soldered
these before without a great deal of trouble.
Thanks for the advice.
georges: First off, it's VERY nonstandard for an LED sheet to include a I/V curve. I don't think I have ever seen one, in fact. The main reason for this is that it varies greatly from one batch to another. The manufacture of an LED die is still a bit of an inexact science (hence the Luxeon Lottery) and so LEDs vary greatly in these characteristics. The other reason that they aren't included is that it really isn't all that important. Overvoltage or overcurrent doesn't kill LEDs the same way it does ICs. What kills LEDs is heat buildup. The packageing on these things is good for 6 watts, so if I do a good job heatsinking it, and actively cool it while it's being tested until I'm sure the current/voltage range is right, then monitor the current on it in a real-life heatsinking situation, I think I will feel comfortable with not having an I/V curves. I spoke to the a rep from the manufacturer of the die (not the assembler of the package) and he said that you really can drive them at 3 or 4 times the rated current as long as you heatsink them properly. I do appreciate the concern, however, and will make every attempt to not fry the LED /ubbthreads/images/graemlins/smile.gif
Edit: Incorrect comment about zeners removed.
Thanks,
Paul