MrAl
Flashlight Enthusiast
Hello again,
FrogBoy:
That's great...i hope you can build this circuit
without too much trouble.
Doug:
You bring up another very good point Doug, as usual
The rationale here is that the draining current when
the light is off is compared to the self discharge
current of a typical NiMH cell. If this draining current
is a small percentage of the normal self discharge then
the drain current is considered acceptable, perhaps even
very acceptable. Now it just so happens that using one
LM339 chip turns out to be approximately 1/8 (that's
one eighth) of the self discharge of a 2000mAh NiMH cell,
so it's deemed 'acceptable'. Using the other comparator
chip specified with the schematic brings even that down
to a very acceptable level. Put another way, the self
discharge initially looks like about a 900 ohm resistor
while the comparator chip looks like around 7500 ohms.
The question then is how much faster do the cells drain
down with 900 ohms in parallel with 7500 ohms as compared
to the 900 ohms alone. Using the CMOS comparator doesnt
even show up on the chart
Of course the reference diode networks bring this up a
little too, about 50ua each. If that's not good enough
then a constant current source would have to be included
for each ref diode. The current decreases quite a bit
when the batterys drain down too.
Take care,
Al
FrogBoy:
That's great...i hope you can build this circuit
without too much trouble.
Doug:
You bring up another very good point Doug, as usual
The rationale here is that the draining current when
the light is off is compared to the self discharge
current of a typical NiMH cell. If this draining current
is a small percentage of the normal self discharge then
the drain current is considered acceptable, perhaps even
very acceptable. Now it just so happens that using one
LM339 chip turns out to be approximately 1/8 (that's
one eighth) of the self discharge of a 2000mAh NiMH cell,
so it's deemed 'acceptable'. Using the other comparator
chip specified with the schematic brings even that down
to a very acceptable level. Put another way, the self
discharge initially looks like about a 900 ohm resistor
while the comparator chip looks like around 7500 ohms.
The question then is how much faster do the cells drain
down with 900 ohms in parallel with 7500 ohms as compared
to the 900 ohms alone. Using the CMOS comparator doesnt
even show up on the chart
Of course the reference diode networks bring this up a
little too, about 50ua each. If that's not good enough
then a constant current source would have to be included
for each ref diode. The current decreases quite a bit
when the batterys drain down too.
Take care,
Al