With two 32600 cells, you are already below the minimum voltage required by the three LEDs, and so the LEDs would be underpowered and the driver would be out of regulation before you started.
Yitao will correct me if I'm wrong, but I believe that the LEDs on his board are in series, so you need to add the Vf of the three LEDs. That is the minimum voltage required for full power. You would need the voltage to be higher than the Vf of the three LEDs in order to have regulation. As the LEDs are in series, 2.8A from the driver will mean that all three LEDs receive 2.8A.
An alternative set up would be having the LEDs in parallel. In that instance, you would only need the power supply's voltage to be equal to the Vf of one LED, or higher to have regulation. However, you would need the power supply to provide 2.8A to each LED - 8.4A total.
Now, presuming that I am correct in stating that the three LEDs are in series, and considering that they have a Vf of approximately 3.3V at 2.8A, that means that you need a minimum of 9.9V to power the three LEDs, rather than 8.4V peak/7.4V nominal.