stevec5000
Newly Enlightened
- Joined
- Jul 11, 2006
- Messages
- 11
I purchased the Brinkmann 3 Watt 2 D cell LED flashlight from woot.com and it's worthless. I just noticed that it was $35 on Amazon yesterday but dropped to $15 today. It's dimmer than a pocket key ring light that uses 1 AAA cell. I checked the specs and the 3 Watt Lumiled is supposed to have 3.7-3.9 volts and that's what makes it work with a power supply on the bench but the flashlight only has 2 D cells putting out 3 volts. It just glows faintly with a yellowish light at 3 volts. How can they expect a 4 volt LED to work with 2 D cells that put out 3 volts? There's almost room in the case for 3 cells that would provide enough voltage to make it work properly but a lot of room in the center of the case is taked up by the switch. Didn't Brinkmann even try this to see if it works before putting it on the market?
One of the reasons I bought it was due to all the good reviews but they seem to be lies. There are lots of reviews giving this light 5 stars and saying it's brighter than a Maglite but that's not possible. Those reviewers must be shills or employees of Brinkmann. It was just $15 but it's a rippoff.
It looks like I might be able to salvage the light by putting 3 C cells in the case by removing the rear spring and allowing the cells to go up into the cap then adding the appropriate voltage dropping resistor to reduce the 4.5 volts to 3.9 volts. Has anyone tried that?
One of the reasons I bought it was due to all the good reviews but they seem to be lies. There are lots of reviews giving this light 5 stars and saying it's brighter than a Maglite but that's not possible. Those reviewers must be shills or employees of Brinkmann. It was just $15 but it's a rippoff.
It looks like I might be able to salvage the light by putting 3 C cells in the case by removing the rear spring and allowing the cells to go up into the cap then adding the appropriate voltage dropping resistor to reduce the 4.5 volts to 3.9 volts. Has anyone tried that?