Subterranean13
Newly Enlightened
- Joined
- Jan 29, 2008
- Messages
- 9
I recently desoldered some L7135 chips from the cheap driver boards when i wanted a lower current from them. I have recently tried soldering some of these onto multimode driver boards that have space for an extra one (dealextreme sku.7612) to try to drive a XP-G at 1400mA (with good heatsinking). However, according to my multimeter, the driver is still acting as though I had not added the extra chip, driving at ~1A on full mode. This was the case with 2 seperate drivers and 2 seperate de-soldered 7135 chips.
I am using a fully charged li-ion 18650 cell, and to check if it was a low voltage problem I very briefly connected a 5.5V source to the driver, yet the same current was drawn (5.5V was connected for literally 2 seconds while the reading was taken, the chips didn't even get warm to the touch). I have checked that the pins of the chip are connected to the equivalent pins of the already present chips and it all seems fine. Is it possible that I damaged the chips when I desoldered them initially? How resiliant are they? Only having one soldering iron i had to leave it in contact with each chip for ~15-20 seconds before all the pins solder melted and it could be removed. Are there any other checks I can do?
Thanks for any help.
I am using a fully charged li-ion 18650 cell, and to check if it was a low voltage problem I very briefly connected a 5.5V source to the driver, yet the same current was drawn (5.5V was connected for literally 2 seconds while the reading was taken, the chips didn't even get warm to the touch). I have checked that the pins of the chip are connected to the equivalent pins of the already present chips and it all seems fine. Is it possible that I damaged the chips when I desoldered them initially? How resiliant are they? Only having one soldering iron i had to leave it in contact with each chip for ~15-20 seconds before all the pins solder melted and it could be removed. Are there any other checks I can do?
Thanks for any help.