uk_caver
Flashlight Enthusiast
I was wondering what might happen if a 'bypass' resistor was added between B+ and LED+ of a buck driver, such that there was always some current flowing from the supply?
The particular application I'm thinking of is for a single LED driver (PT4105/AX2002) which is running off 4 AAs, so typically ~5V input with NiMHs, via a single-level driver.
The idea is to add some redundancy at the expense of a little efficiency, with a resistor chosen to pass a fairly small fraction of the total power, maybe 20% at maximum battery voltage.
I'll cobble together a test circuit and let it run on the bench, but I was wondering if someone could say with confidence whether the idea is likely to be absolutely fine, or whether it might introduce any kind of instability into the circuit?
The particular application I'm thinking of is for a single LED driver (PT4105/AX2002) which is running off 4 AAs, so typically ~5V input with NiMHs, via a single-level driver.
The idea is to add some redundancy at the expense of a little efficiency, with a resistor chosen to pass a fairly small fraction of the total power, maybe 20% at maximum battery voltage.
I'll cobble together a test circuit and let it run on the bench, but I was wondering if someone could say with confidence whether the idea is likely to be absolutely fine, or whether it might introduce any kind of instability into the circuit?
