Candle conversion

[Deep Blue]

Hiii

I have some Questions :

Q1: How can i convert between candle with lumens?
if 1,000,000 candel power = how many lumens ?

Q2: How can i convert between Watt with Ampere?
if 35 Watt bulbe = how many Ampere of energe the bulbe use?

Regards;

 

[KeyGrip]

I'm not too good with electrical terms yet, but I can answer Q1:
There is no conversion. Candlepower and lumens measure two different things. Often, candlepower ratings on lights are hugely overblown, and used as nothing more than a marketing technique.

 

[Qoose]

This may be hijacking the thread, but I've been wondering this all day. Could you convert between lumens and candlepower? I was thinking of how to calculate using spot candlepower calibration and them a beamshot. For example if you had a nice round beamshot, take a measurement of every patch between the edge of spill and the center, then map it out using some math. That should give you a rough calculation of lumens.

Some assembly required. Either that or I've been looking into my flashlights to much.

 

[paulr]

This may be hijacking the thread, but I've been wondering this all day. Could you convert between lumens and candlepower? I was thinking of how to calculate using spot candlepower calibration and them a beamshot. For example if you had a nice round beamshot, take a measurement of every patch between the edge of spill and the center, then map it out using some math. That should give you a rough calculation of lumens.

Some assembly required. Either that or I've been looking into my flashlights to much.

Yes, the relevant definitions are at

http://en.wikipedia.org/wiki/Lumen_(unit)

and the articles linked from there.

 

[TigerhawkT3]

See the Welcome Mat in Questions/Problems/Suggestions.

 

[mdocod]

Q2: How can i convert between Watt with Ampere?
if 35 Watt bulbe = how many Ampere of energe the bulbe use?

Think of Amps as current, flow. cubic foot per minute from an air hose.

Think of Volts as the pressure behind the flow. Like PSI in a compressor.

Multiply pressure by flow and you are using some quantity of energy, in electrical terms, we call that watts.

Volts x Amps = Watts.

So you are asking how many amps a 35W bulb pulls. Well, as you can see from the formula, you can't determine amps until you have determined volts, or vice versa, need to know at least 2 things to find the 3rd.

A 6V 35W bulb would have to run at ~5.833A.
A 120V 35W bulb would only run at ~0.29166A.
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For question 1. the simple answer is to take all of the people in charge of PR and advertising for a given spotlight manufacture, round them up into a pen, measure the size of their rumps, rounded to the nearest whole number, add them all up and call that "X", then find RMS value of combined fecal excitements over the first 24 hours, call that "Y"... Then multiply X x Y, then just go ahead and add a random number between 250,000 and 18,500,000. That's CandlePower. The problem with this method is that there is no mathematical conversion for fecal excrement to lumens.

 

[TigerhawkT3]

Howzabout I just copy and paste from my Welcome Mat.

Q: What's the difference between "lumens" and "lux"?
A: Lumens measure the total amount of light output from a particular source. Lux measures the intensity of the light hitting a specified area. For example, an ordinary household lightbulb generates about 1000 lumens, but the intensity of its light at a particular point, such as on a book you're reading, will be comfortably low. Almost all flashlights rely on an optical device such as a reflector or lens to squeeze most of their output into a small area, which allows you to illuminate a point of interest with enough intensity, but without requiring a lot of power. To illustrate this concept, try the following: First, look at your room's ceiling light. In all likelihood, you can stare at it without much discomfort. Now, try looking into a weak flashlight like a traditional incandescent Mini-Maglite. You'll notice that it seems very bright. This is lux. Now, remove your Minimag's head to put it into candle mode. Try switching between its output and your ceiling light's output. Since they're now illuminating approximately the same area, the much higher lumen value of the ceiling light will provide much higher lux values at a chosen point. An extreme example of high lux and low lumens is a laser, which doesn't really create that much light, but focuses it into a tiny, brilliant point.

Q: Please explain volts, amps, watts, and C.
A: That's not a question, but okay. Volts are electrical potential, amps are electrical current, watts are total power equal to volts*amps, and C is electrical current as a function of battery capacity. Think of volts as the width of a pipe: In general, a wider pipe has more punch than a narrower one. Think of amps as the water flowing through a pipe: Some pipes can only handle little trickles of water, and others can handle lots of water pushing through with great force. Think of watts as a combination of volts (pipe width) and amps (flow of water): A large pipe with water flowing through really slowly has the same output as a small pipe with water blasting through it. This is why high-voltage applications are preferred over high-current applications, as a stream of water zooming at 200mph through a 1"-diameter pipe is much more dangerous and difficult to maintain than a calm, 3mph flow of water through a 4'-diameter pipe. As for C rates, that's just a function of current draw and battery capacity. Any power source discharged at a 1C rate will be depleted in 1 hour, any power source discharged at a .25C (or C/4) rate will be depleted in 4 hours, and so on. As an example, a 1.8Ah AA NiMH capable of an excellent 10C discharge rate can manage 1.8*10=18 amps.