DB1200s ???

[darkzero]

I've heard of these, are they a myth? How do you obtain one of them? Must you change/add the resistors yourself? If so where do you get .04 ohm or two .08 ohm SMD resistors of this size if there are such things?
Appreciate any info.
TIA

 

[kj]

You need to add, actually stack, a resistor by yourself. I doubt Wayne will offer this as a standard configuration since it's a kind of overdrive. Buy DB700, which should have 0.12 and 0.18 ohm resistors, and stack a 0.1 ohm resistor with one of the exising resistors. Strictly speaking, it's 1194, but 1200 approx.

 

[PieThatCorner]

dark, if you end up modding a DownBoy into a 1200 and make another one of your McLux PR heads, then you've got an instant customer right here. /ubbthreads/images/graemlins/grin.gif

-Jim

 

[darkzero]

kj, appreciate the valuable info, thanks! /ubbthreads/images/graemlins/thumbsup.gif
Now to save up a bit more cash for you know what.... /ubbthreads/images/graemlins/grin.gif

Jim, you are not & will not be forgotten. /ubbthreads/images/graemlins/thumbsup.gif
I'll be in touch.....

-Will-

 

[darkzero]

[ QUOTE ]
kj said:
You need to add, actually stack, a resistor by yourself. I doubt Wayne will offer this as a standard configuration since it's a kind of overdrive. Buy DB700, which should have 0.12 and 0.18 ohm resistors, and stack a 0.1 ohm resistor with one of the exising resistors. Strictly speaking, it's 1194, but 1200 approx.


[/ QUOTE ]

kj, for DB1200....
Another way instead of using a .12 ohm and a .18 ohm resistors, and stacking a .1 ohm resistor with one of them, which equals a parallel resistance of 0.04186046511627907, to get 1194; I could also use a .12 ohm and a .15 ohm resistor and stack a .1 ohm resistor with one of them, which equals a parallel resistance of exactly .040, to get 1250.
Was that correct?

(man that is alot of calculating...I cheated a bit though and used some online calculators to help /ubbthreads/images/graemlins/grinser2.gif)
I'm still learning all of this
thx

 

[kj]

Correct. I realized you mentioned 0.04 ohm resistor and that makes 1250. The combination of 0.1, 0.12 and 0.15 should give you the same result.