alexlockhart
Newly Enlightened
- Joined
- Jun 27, 2007
- Messages
- 60
I have a Cateye HL-EL510 bike light. I got the older HL-EL500 when it first came out like 4 years ago, and was impressed at its brightness and long run time. The newer 510 that I've had now for about 2 years seems to have the same overall brightness, but has a tight oval beam with some spill, which is an excellent pattern for commuting (my main riding).
With the newer, more efficient LEDs available now, I've been thinking about modding my light to use one of them. The 510 uses a plain Luxeon I lambertian emitter, and from my calculations of burn time (30 hours on 4xAA) it drives it at about 150mA. Probably less, since the driver can't be perfectly efficient. Of course, that's far less than it could be driving, even the LuxI, but that's done because the battery life is a strong selling point for this light. 20 lumens or so, if it's well-focused, is enough for the cheap battery-powered LED light market.
I know the SSCP4 has the exact same physical characteristics as the LuxI, so I know I could just un-solder the LuxI and solder in the SSCP4, but it's slightly different electrically. The biggest difference that I can see is its Vf is 3.25, whereas the LuxI's Vf is 3.47. Before I do the mod, I want to know how the new LED will be driven.
That depends on the driver, of course, which in this case is basically a simple resistor. The light has a high and low beam mode, and it takes the 6V from the batteries (4.8V from my NiMHs) and transforms that to something the LED likes, so it's got other stuff besides a resistor in there, but it doesn't do any real regulating - it slowly gets dimmer and dimmer as the batteries wear down.
I took the light apart the other night, and besides a few unrecognizable components, and 2 things covered in goo (by design), there's a 510mOhm resistor in there that's big enough to be the one that's the current-limiting one. I did some electronics math ( at http://ourworld.compuserve.com/homepages/Bill_Bowden/led.htm) and figured that, if it's driving the LED at 150mA, then the input voltage (before the resistor) must be 3.5 volts.
So, I'm wondering what will happen when I drop in an LED with a lower Vf. The calculations for the resistor-based driver seem to suggest that changing the Vf to 3.25 and leaving the input voltage and resistor the same means a current draw of 500mA. That would be a welcome boost to around 120 lumens, but the chart describing Vf versus mA for the SSCP4 seems to indicate that 500mA draw happens around 3.4V, not 3.25V. So I'm not sure what would happen - the driver seems to say one thing, the LED another.
Thinking about this much higher drain on the batteries, and finding out that there are Li-Ion cells that are shaped like an AA, I thought that maybe I could upgrade the batteries in the light as well. Since the light is designed for 4xAA in series, it can certainly handle 6V, so if I rewire the battery compartment to use 4x14500 in a 2S2P configuration, I'll be giving it 7.2V. To find out what would happen if I just dropped those batteries in right now, I wired 6xAA in series (which, with NiMH, is 7.2V) and fed it to the light. It was brighter, but not a lot. I took some beamshots, but they weren't very impressive - it looks maybe 20% brighter with 6xAA vs. the original 4xAA, despite a 50% increase in voltage. I don't have a multimeter, so I couldn't measure the current draw on the batteries in either configuration, and couldn't measure actual voltage delivered to the LED either.
OK, that's what I've figured out so far. Now it's time for you to tell me the things I don't know: What current draw, and at what Vf, will the SSCP4 have if I just drop it in? How about if I use 4x14500 in 2S2P, making the supply (before the regulator) 7.2V instead of 4.8V?
Alex
With the newer, more efficient LEDs available now, I've been thinking about modding my light to use one of them. The 510 uses a plain Luxeon I lambertian emitter, and from my calculations of burn time (30 hours on 4xAA) it drives it at about 150mA. Probably less, since the driver can't be perfectly efficient. Of course, that's far less than it could be driving, even the LuxI, but that's done because the battery life is a strong selling point for this light. 20 lumens or so, if it's well-focused, is enough for the cheap battery-powered LED light market.
I know the SSCP4 has the exact same physical characteristics as the LuxI, so I know I could just un-solder the LuxI and solder in the SSCP4, but it's slightly different electrically. The biggest difference that I can see is its Vf is 3.25, whereas the LuxI's Vf is 3.47. Before I do the mod, I want to know how the new LED will be driven.
That depends on the driver, of course, which in this case is basically a simple resistor. The light has a high and low beam mode, and it takes the 6V from the batteries (4.8V from my NiMHs) and transforms that to something the LED likes, so it's got other stuff besides a resistor in there, but it doesn't do any real regulating - it slowly gets dimmer and dimmer as the batteries wear down.
I took the light apart the other night, and besides a few unrecognizable components, and 2 things covered in goo (by design), there's a 510mOhm resistor in there that's big enough to be the one that's the current-limiting one. I did some electronics math ( at http://ourworld.compuserve.com/homepages/Bill_Bowden/led.htm) and figured that, if it's driving the LED at 150mA, then the input voltage (before the resistor) must be 3.5 volts.
So, I'm wondering what will happen when I drop in an LED with a lower Vf. The calculations for the resistor-based driver seem to suggest that changing the Vf to 3.25 and leaving the input voltage and resistor the same means a current draw of 500mA. That would be a welcome boost to around 120 lumens, but the chart describing Vf versus mA for the SSCP4 seems to indicate that 500mA draw happens around 3.4V, not 3.25V. So I'm not sure what would happen - the driver seems to say one thing, the LED another.
Thinking about this much higher drain on the batteries, and finding out that there are Li-Ion cells that are shaped like an AA, I thought that maybe I could upgrade the batteries in the light as well. Since the light is designed for 4xAA in series, it can certainly handle 6V, so if I rewire the battery compartment to use 4x14500 in a 2S2P configuration, I'll be giving it 7.2V. To find out what would happen if I just dropped those batteries in right now, I wired 6xAA in series (which, with NiMH, is 7.2V) and fed it to the light. It was brighter, but not a lot. I took some beamshots, but they weren't very impressive - it looks maybe 20% brighter with 6xAA vs. the original 4xAA, despite a 50% increase in voltage. I don't have a multimeter, so I couldn't measure the current draw on the batteries in either configuration, and couldn't measure actual voltage delivered to the LED either.
OK, that's what I've figured out so far. Now it's time for you to tell me the things I don't know: What current draw, and at what Vf, will the SSCP4 have if I just drop it in? How about if I use 4x14500 in 2S2P, making the supply (before the regulator) 7.2V instead of 4.8V?
Alex