Xcandescent
Newly Enlightened
- Joined
- May 23, 2002
- Messages
- 60
I'm new to the forum, and my electronics knowledge is extremely limited, so please -- be gentle.
I've been working on hacking (quite literally) an external lighting fixture for the Game Boy Advance. My intent is to power 2 white LED's (Vf=3.6V; I=20mA) from the Link Port, which provides either 3.3V or 5V depending on what type of game you're playing. I figured the best way to do this was to use a DC-DC boost converter, so I ordered some samples of National's LM2703.
The problem is I haven't enough knowledge to actually understand how to use it, or why certain circuit configurations work. I've noticed that most boost converters utilize some sort of feedback loop with 2 resistors to set output voltage -- but often replace the first resistor with the LEDs to be powered. I have no idea how/why this works, or how one would set the voltage properly in that case.
In the case of the LM2703, the two resistors used to set output voltage are expressed as functions of each other and Vout. Vout is known, but it's not clear to me whether either resistor value can be arbitrarily set (and then the second resistor solved for), or whether there's a secondary condition which must be met. If anyone knows, I could sure use the advice!
(Yes, to someone who knows what they're doing, I'm sure that sounds like a complete newbie question. I TOLD you my electronics knowledge is limited ...)
-XCN-
I've been working on hacking (quite literally) an external lighting fixture for the Game Boy Advance. My intent is to power 2 white LED's (Vf=3.6V; I=20mA) from the Link Port, which provides either 3.3V or 5V depending on what type of game you're playing. I figured the best way to do this was to use a DC-DC boost converter, so I ordered some samples of National's LM2703.
The problem is I haven't enough knowledge to actually understand how to use it, or why certain circuit configurations work. I've noticed that most boost converters utilize some sort of feedback loop with 2 resistors to set output voltage -- but often replace the first resistor with the LEDs to be powered. I have no idea how/why this works, or how one would set the voltage properly in that case.
In the case of the LM2703, the two resistors used to set output voltage are expressed as functions of each other and Vout. Vout is known, but it's not clear to me whether either resistor value can be arbitrarily set (and then the second resistor solved for), or whether there's a secondary condition which must be met. If anyone knows, I could sure use the advice!
(Yes, to someone who knows what they're doing, I'm sure that sounds like a complete newbie question. I TOLD you my electronics knowledge is limited ...)
-XCN-