SSC P7 and 6 x AA NiMH ... safe at 2.8A?

Magic Matt

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Dec 22, 2009
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Near to Portsmouth, Hampshire in the UK
Every time I post these, I'm sure I can hear some of the more learned members chuckling to themselves. Yes, it's me again, and I've done yet more searching and reading, and could do with a sanity check for my plan.

Posting in the batteries section because I think this is more a battery questionn than anything else... feel free to whack me with the n00b-stick if not. ;)

I think the hipCC controller (link below) seems like the best suited to what I want to do, which is drive the P7 at various levels via PWM. I don't know if I'll try to build my own controller, or buy one (the hipFlex is slightly too large to fit into my donor body).


I intend to build myself some sort of 6P AA holder to fit in a 2D space. Here's my thinking that I think needs checking... would somebody mind getting the red teachers pen out? ;)


  • 6P AA NiMH cells, at 0.1ohm internal resistance gives me a total resistance of 0.6ohm for the cells.
  • Each cell has 1.25V (avg) to 1.4V (max) meaning the total voltage will be between 7.5V and 8.4V
  • I'm intending to use Eneloops which means that my capacity will be 2000mAh because they're connected in series.
  • I = V/R so my theoretical maximum current is going to be (8.4V * 0.6 ohm) = 5.04Amp and my maximum current during the life of the battery will be (7.5V * 0.6 ohm) = 4.5A
I think the sweet-spot for the cells is 0.5A and I think I understand that if I run them at more than 0.5A for any length of time I wont get the actual capacity of the cell.

What I don't understand is where the safe maximum is. Obviously at 4.5A that's basically short circuiting the cells, and all the power would be expelled from the battery as heat ... :poof:

Am I ok to pull 2.8A from the cells without damaging them? To clarify, I intend to do this under a "turbo" scenario in burst of a few minutes, but I don't want to damage anything if it were to be left on turbo until the cells are flat.

Assuming it's ok, is there a way to work out how hot they will get, and how long they will actually last compared to a theoretical time span (2.8A @ 2Ah = about 43 mins)?

Is there a 'low voltage' beyond which you shouldn't discharge an NiMH, like there is with Li-ion cells?
 
6 NiMh --> 7,2V
1 P7 --> 3,5V --> 2,8A

Battery current: roundabout 1,4A ;)

Lowvoltage: 1V/cell
 
I = V/R so my theoretical maximum current is going to be (8.4V * 0.6 ohm) = 5.04Amp and my maximum current during the life of the battery will be (7.5V * 0.6 ohm) = 4.5A

Recheck your math. Should be (8.4V / 0.6 ohm) = 14Amp and (7.5V / 0.6 ohm) = 12.5A
 
6P means 6 cells in parallel. If you plan to make a holder for six cells in series, you are talking about 6S.

For AA Eneloop performance, see this thread.

The key driver equation is

driver efficiency * Vbatt * Ibatt = Vf * Idrive

If you have a P7 with a nominal Vf of say 3.5V at 2.8A drive current (9.8W draw), then

driver efficiency * Vbatt * Ibatt ~ 9.8W

The above equation simply equates driver power generated to LED power draw.

For six AA NiMH cells in series, you might expect about 1.25V per cell under load, based on the link I provided above. We can also assume a driver efficiency of say 85% just to plug in a reasonable number.

Thus,

Ibatt ~ 9.8/(0.85*7.5) = 1.5A

in agreement with T24's estimate. Ibatt might be higher or lower by a little depending on the actual Vbatt under load and the true driver efficiency. But the estimated Ibatt isn't going to be vastly off.
 
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