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Thread: Standby drain of Peak lights?

  1. #1

    Default Standby drain of Peak lights?

    Hi,

    I am new to Peak lights. I am curious what are the standby drain current on the peak lights? The parasitic current at off. Thanks!

  2. #2
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    Default Re: Standby drain of Peak lights?

    Zero ... none
    ... is the archimedes peak

  3. #3
    Flashaholic* Thetasigma's Avatar
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    Default Re: Standby drain of Peak lights?

    Zero unless left on

  4. #4

    Default Re: Standby drain of Peak lights?

    Not even 1 μA?

  5. #5
    *Flashaholic* Str8stroke's Avatar
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    Default Re: Standby drain of Peak lights?

    When unscrewed, there is zero contact. All twist lights are this way. You are breaking the connection.
    Interested in Saltytri lights. Pm me!


  6. #6
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    Default Re: Standby drain of Peak lights?

    It is an open circuit when off .... Mechanically locked out.
    Last edited by archimedes; 08-03-2016 at 07:53 PM.
    ... is the archimedes peak

  7. #7
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    Default Re: Standby drain of Peak lights?

    Quote Originally Posted by Str8stroke View Post
    When unscrewed, there is zero contact. All twist lights are this way. You are breaking the connection.
    Would clarify that it depends on exactly how you want to define "twist lights" , but I would say most (but not necessarily all) twist lights break continuity in this manner.
    Last edited by archimedes; 08-03-2016 at 08:04 PM.
    ... is the archimedes peak

  8. #8

    Default Re: Standby drain of Peak lights?

    That's awesome! I thought it's similar to the magnetic ring infinitely variable control, which usually renders a high standby current.

  9. #9
    Flashaholic* Thetasigma's Avatar
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    Default Re: Standby drain of Peak lights?

    Peak lights use a little tab of QTC material to allow the variable output. The QTC is a perfect t insulator when uncompressed, but once you start to apply pressure by twisting the light it starts to allow current through. The current curve is roughly logarithmic so the actual output happens to appear linear to our eyes.
    The downside is the material breaks down from use do to shear forces in the pill holder. However if you can get the pill apart it is replaceable.
    The El Capitan and the Logan have better control over the output than the Eiger due to their larger diameters

  10. #10

    Default Re: Standby drain of Peak lights?

    Quote Originally Posted by Thetasigma View Post
    Peak lights use a little tab of QTC material to allow the variable output. The QTC is a perfect t insulator when uncompressed, but once you start to apply pressure by twisting the light it starts to allow current through. The current curve is roughly logarithmic so the actual output happens to appear linear to our eyes.
    The downside is the material breaks down from use do to shear forces in the pill holder. However if you can get the pill apart it is replaceable.
    The El Capitan and the Logan have better control over the output than the Eiger due to their larger diameters
    Thanks for the detailed explanation. I am assuming the QTC resistor is in series with the LED. In this case won't it waste a lot of energy since current run through it?
    Or, is QTC only in the control circuit with very small current going through it?

  11. #11

    Default Re: Standby drain of Peak lights?

    Yes, the QTC material acts as a variable resistor. It has exceptional current handling capabilities and it is essentially in series with the battery and the LED/driver. There is no fancy microcontroller like a magnetic ring requires. If the circuit is open then there will be no drain.

    Efficiency is good at max because resistance is near zero. Efficiency is okay at moonlight because there is no MCU overhead. Efficiency is so-so over the mid range.
    Last edited by parametrek; 08-04-2016 at 10:20 AM.
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  12. #12

    Default Re: Standby drain of Peak lights?

    Quote Originally Posted by parametrek View Post
    Yes, the QTC material acts as a variable resistor. It has exceptional current handling capabilities and it is essentially in series with the battery and the LED/driver. There is no fancy microcontroller like a magnetic ring requires. If the circuit is open then there will be no drain.

    Efficiency is good at max because resistance is near zero. Efficiency is okay at moonlight because there is no MCU overhead. Efficiency is so-so over the mid range.
    Thanks a lot for the clear explanation!

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