For a projection of the surface of the LED.
How do you calculate the viewing angle/projection angle/magnification?
With a 1.4mm (2mm^2) diode surface, I measured that a 15mm focal length lens gave me a roughly 12deg projection angle.
Using the same 1.4mm diode, a 10mm FL produced about a 24deg viewing angle.
(actual projection being about 4X as large as the 15mm FL)
What must the FL be to give me a roughly 12deg projection angle on a 1mm (1mm^2) diode?
The following formula is the best thing I could find, but it yields slightly different numbers than what I'm actually seeing.
Viewing angle (alpha) = 2arctan(d/2f) where d=projection diagonal and f=FL
Using a diode width of 1.41mm and FL of 15, the eqtn gives me an angle of 5.38deg. Why does my actual physical test vary?
It seems that if I use the formula 4arctan(d/2f) it is almost completely accurate to my real measurements...
How do you calculate the viewing angle/projection angle/magnification?
With a 1.4mm (2mm^2) diode surface, I measured that a 15mm focal length lens gave me a roughly 12deg projection angle.
Using the same 1.4mm diode, a 10mm FL produced about a 24deg viewing angle.
(actual projection being about 4X as large as the 15mm FL)
What must the FL be to give me a roughly 12deg projection angle on a 1mm (1mm^2) diode?
The following formula is the best thing I could find, but it yields slightly different numbers than what I'm actually seeing.
Viewing angle (alpha) = 2arctan(d/2f) where d=projection diagonal and f=FL
Using a diode width of 1.41mm and FL of 15, the eqtn gives me an angle of 5.38deg. Why does my actual physical test vary?
It seems that if I use the formula 4arctan(d/2f) it is almost completely accurate to my real measurements...
Last edited: