Vermonter73
Enlightened
- Joined
- Jul 25, 2006
- Messages
- 335
How much material would I need to remove to fit a protected 18650 in a 6P? I don't have a 6P yet. Does the head and tail come off to allow straight-through access for sandpaper on a drill?
+1most people use a 19mm drill bit.
The OD for a typical SureFire 6P (measured at the thinnest point, the tail o-ring grooves), is ~0.771" (19.6 mm) with a wall thickness of ~ 0.042".
Taking the ID to 0.734" (18.6 mm) results in a wall thickness of 0.0185". IMO this is optimum for the AW 2600 mAH 18650's, providing a clearance of only ~0.006" (~0.003" on each side) for my particular cells.
Taking the ID to 0.741" (18.8 mm) results in a wall thickness of 0.015".
Taking the ID all the way up to 19.0 mm would result in a wall thickness of only 0.011", ~1/4 of the original wall thickness. This is the same thickness of a typical paper business card, which would concern me with regards to structural strength.
(regarding HKJ's cell measurements), The OP does need to consider what cells he will be using.
Does the head and tail come off to allow straight-through access for sandpaper on a drill?
18.6 mm does sound like the perfect number. A 47/64" twist drill will make a hole .7344", or 18.65 mm.Taking the ID to 0.734" (18.6 mm) results in a wall thickness of 0.0185".
18.6 mm does sound like the perfect number. A 47/64" twist drill will make a hole .7344", or 18.65 mm.
This is exactly what ElectronGuru ships, and it is perfect!
A twist drill that has sharp lands can do a good job enlarging a hole, and takes almost no time. Same for a reamer except that the reamer is more accurate for final diameter & leaves a nicer finish.Why not do it exclusively with the boring bar?
I use a 47/64" reamer, and it works very well. I found I get much better results running very slowly and using lots of cutting oil.18.6 mm does sound like the perfect number. A 47/64" twist drill will make a hole .7344", or 18.65 mm.