I am working on a two color (amber/cyan) light. If you look at the
1931 CIE color chart, the outside edge represents monochromatic lights. A 1-color LED has a pretty narrow range so it would be just a little inside the edge. Draw a line from one point on the edge (one color) to another point on the edge, and you can mix those colors to get any color along the line.
Usually they use 3 colors to make a triangle. Then you can mix them to get any color within the triangle. Since my goal is to basically follow the blackbody curve, I hope to do that with only 2 colors.
I assume you aren't concerned with CRI then? A 2-color light can make "white", but the fact that there are only 2 colors effectively means that the chromatic range seen will approximate what a color-blind persons sees.
I've been trying to do the same thing myself, but the problem for a red-cyan setup is that the left side of the CIE curve is much more spaced out than the right side; the slightest variation in nanometers can turn a two-color red/cyan light from yellowish to magenta. I'm not aware of any LED retailer who can deliver a diode within one or two nm.
A blue-yellow might be easier, using a blue (470nm) or royal blue (450nm), but now you need a yellow emitter in the 570nm range or so; amber Lux I's and III's top out around 589nm. I've never seen any Lux or other such emitter in wavelengths like that.
Your luck might improve in 5mm, but I don't know where small quantities at specific wavelengths can be had. (I would love to know, though, as I've got a bunch of 1st gen blue Inova X1's waiting for mods.)
As for blackbody, it's not a straight line through the CIE space, so I doubt you'll be able to get it with two monochrome sources.
Ah, just read your last post. Yes, 640nm or so is probably what you need, if you are working from high color temp whites. Check The LED Museum site, he's got all kinds of spectrographs for various different emitters that might give you an idea of where to bolster the spectrum of your sources.