To answer your question:
It's probably worth sorting out the mAH thingies! <G>
There are chargers out there now that are far more fast, sophisticated and programmable than what you have. They don't cost much more than a set of cells (batteries) and usually come _with_ a set anyway.
From the pictures I can't be sure exactly how the thing is set up to take cells, but:
The trouble with timed chargers is that they take no account of the state of charge of the cell(s). They can overcharge. At 190 mA....I would not be happy leaving a half-charged cell in there for the full 15 hours. I doubt it would do anything drastic, but may lower the number of recharges.
Your charger might _juuuuust_ make it with a completely flat cell, if it fact puts out 190 mA in that second picture. It says 170-190, and I do not know what decides that. If it's less than 190 mA, then the charger will definitely not charge your cells.
- 190 mA * 15 hours (timed charge)= 2850 mAH put into the cell.
- 2500 mAH cell capacity * 1.2 (charge deficit: see below)= 3000 maH
So really it will struggle to properly fill the cell(s). It will take a long time to charge more than 2. After you have done a timed charge, I would top the cell(s) up using that even lower current mentioned in the second picture (if you can choose), which should not do any damage if you leave it too long, because it's so low.
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milliAmps (mA) are current. For a given voltage, the more mA the more power is delivered.
milliAmpHours mAH, are just that. The capacity of a cell in mAH is the (CLAIMED) number of hours that it will take to drain the cell at 1mA, from fully-charged to the point where it's not good to drain the cell without recharging. It's a very slippery figure.
Usually this is not useful, because we use more than 1 mA in most uses, and 1 mA is probably less than the cell will lose just sitting there! So if the current is 100 mA, the number of hours would be 2500 / 100 = 25 hours of continuous use. 1 Amp = 1000mA. So if you use 1 Amp you get 2.5 hours use.
In the other direction, you need to charge the cell, and you can get some idea of how long it will take at a given current by exactly the same method. However, it takes maybe 20% more energy to "push the charge back in" than the cell will give you when fully charged. This is what I called the "charge deficit" above. That's just my choice of term.
Nick