Building a battery pack

bnemmie

Enlightened
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Jan 13, 2010
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226
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The UP
So I have a Pelican 8060 that I love. It has its own rechargable 4 cell 4.8v 4.6Ah battery pack, but it will also take normal 'C' batteries. I was thinking about getting 4 of these and building my own battery pack:

http://www.batteryjunction.com/tpeh-t6000.html

If all goes well the new 4 cell battery pack will be 4.4v and 240Ah.....right?

And it should work and extend the run time quite a bit....right?

And I won't mess up my $150 flashlight or waste my money on something that wont work....right?

The main concern I have is the new pack will be .4v less then the old.
Any thoughts? Thanks in advance all.
 
So I have a Pelican 8060 that I love. It has its own rechargable 4 cell 4.8v 4.6Ah battery pack, but it will also take normal 'C' batteries. I was thinking about getting 4 of these and building my own battery pack:

http://www.batteryjunction.com/tpeh-t6000.html

If all goes well the new 4 cell battery pack will be 4.4v and 240Ah.....right?

And it should work and extend the run time quite a bit....right?

And I won't mess up my $150 flashlight or waste my money on something that wont work....right?

The main concern I have is the new pack will be .4v less then the old.
Any thoughts? Thanks in advance all.

no it wont be 4.4v and 240Ah..... thou i'd be curious to see where you got those numbers,

4.8v 6ah and you wont get extend the run time quite a bit...., just a little bit, 20% or so

and why do you wanna build the pack???? just use those new cells as you would normal c cells, don't worry about v difference
 
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Its my first time building a battery pack, so i thought that if i have 4 cells at 6000mAh each then that would translate into more run time.
4 x 6,000 mAh = 24,000 mAh = 24 Ah right? (i may have added an unnecessary 0 in my last post) my ultimate goal would be to use the new bigger cells in the flashlight and be able to charge it like normal, in the charging dock. not have to take them out to put them in a special charger or anything.
 
4 x 6,000 mAh = 24,000 mAh = 24 Ah right? .
wrong.
it would be right if you wired them in paralell, but it would give you 1,2v.

again, there is no need to build a pack, just load new cells in and you're done.
 
ahh ok, thats what i get for thinking. lol well thank you for the info. ill do just that and see how she works out. thanks again.
 
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