dx 7880 regulator efficiency

lolzertank

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I'm planning to get a Romisen RC-G2 and replace the driver and led with a cree xr-e q5 and a this 20 mode driver(sku 7880). Does anyone know the efficiency for this driver? Also, could you post the current going to the led? I know the specs say 800ma, but I want to hear some real measurements since I'm not so sure i trust dealextreme's.
 
Hello, and welcome to CPF.

There was a similar question to this posted just a few days ago in fact. I would suggest you do a search at the top of the board here for 7880. Do a little reading and come back with any specific questions.
 
Do you mean the first post on this thread? http://www.candlepowerforums.com/vb/showthread.php?t=188227
"3W/5W" 1x AA. $3.96. Boost board; output voltage and current not constant, approximately 0.8-1.5 V in. 1.0 V in gives 0.3A out, 1.4 V in gives 0.7 A out. Run on two fresh NiMH it gets very hot - not advised. 20 modes in three groups.

Combining what it says with other posts saying it draws about 2-3 A from the battery, would this mean this board has about a 70% efficiency? Hope my math is correct...:thinking:
 
It seems people have had different experiences with that board. I have seen reports of outputs at 600 mA as well. And I now see on the driver thread there are actually 2 different links to it, 1 mentioning 1xAA and one says .8-7V in. I wonder if that one is a typo?

There are probably different ways to figure efficiency but what I do is simply figure watts going into the circuit and watts going out, and then a percentage of such.

So, if it takes for instance.

1.2Vx3A=3.6W in.
3.4Vx.8=2,72W out.
2.72/3.6=75.55

Rizki_p who is also a member here reported "Am i the only one who get 0.3A output and 0.8A draws from the battery, mine doesnt draws 3A like most people indicated. " on the DX comments there.

Efficiency will be effected by resistance in the circuit as well including how you measure the current. Others have mentioned a better way to figure the current at the led by measuring the voltage and somehow figuring the drop using ohm's law, I don't recall how. I think you had to measure it against a known value resistor. I have been measuring it through a shunt meter which does introduce resistance and skew your #'s a bit.

This link here shows 2 different equations for efficiency:
http://www.mobilehandsetdesignline.com/howto/207000658

The #'s I gave above are pretty rough figures. There are other members much more versed in electronics that could explain better.
 
Thanks everyone for your help. I've ordered it, but its backordered. I'll probably take my own measurements when I get it. Hopefully it won't output 0.3 A like Rizki_p's. 75% efficiency doesn't sound TOO bad for a 1xAA boost circuit.
 
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