I have disassembled a protected battery here. But to be used with the circuit removed it needs some heat-shrink tubing around it.
Is that because the metal shell of the cell will short to the inside of the tube and bypass the switch?
Just testing my understanding of things.
--flatline
I am totally going to remove the protection from the ultrafire(?) 14500s I bought. I trust the protection built into my LF5XT way more than the circuit on the cells and the circuit on the cells is wider than the cell is, so I had to file it down to fit in the light (which makes me worry about shorting the cell).
In the case of the LF5XT, if the cell shorts to the inner tube, that should be okay since there is no switch between the base of the inner tube and the tube itself. Right? It just carries power to the head of the light?
Clearly, I need to examine the design of the LF5XT before I try this...
--flatline
Remember also though, that you will be handling and recharging it, so you should anticipate all the other ways you might accidentally short it==>Murhpy's Law.
I need to remove the protection circuit of a 10440
*Sorry to dig up an old post*
i too would like a little advice :help: .. after removing the PCB is it necessary to remove the wire that runs from end to end or can this just be left in place to save removing the wrapper from the cell?
Definitely remove the wire and rewrap the cell.
...the loose end might even be able to short your cell out directly. That could happen at any time: on the charger, sitting on your desk, or packed away in a storage box, for example.
Can you use electrical tape for a re-wrap?